Marking 2 Review Notes
You are expected to sign up for AT LEAST 2 sections. Besides giving some explanation about the section you must answer the BIG IDEA Question for your section. You may need to do some work and use photobooth to take a picture of your work and post it on the page.
Section
Name
Name
Name
Name
3-2 -
Jess G.
Michlle
Zach
Richard
Kevin D
3-3
Jeff
Dylan
Jess G
Jess R
3-4
Brit
Kim
Zach
Richard
5-1
Max
Donteris
Jess R.
Will
5-2
Max
Donteris
Kim
Will
5-3
Jeff
Brady
Alexis
Jack
5-4
Rachel
Brady
Alexis
Jack
Natalie
5-5
Kevin D
Dan
Brit
Natalie
5-6
Dan
Michelle
Dylan
Rachel
Insert Table
3-2 You would like to minimize the amount of work required to solve a system of equations. Tell whether you would solve each system using substitution or elimination and why.
Michelle: In order to solves this system of equations you must first look at each equation individually.
Equations
Steps
Reasons
2x+y=18
y=2
Substitute in (y=2) in the equation (2x+y=18) to make 2x+2=18.----
Subtract 2 from both sides. The equation is now 2x=16.
Then divide both sides by 2 and get x=8.
You would use substitution for this example because y is already by itself, therefore making it easier for you to replace the y in the first equation with the value of y in the second.
3x+y=-7
x-y=-5
Eliminate the y value in both equations because they are opposites by adding both equations together. Ending with 4x=-12.
X=-3
Then plug in the X value to either of the original equations to get the Y
You would use elimination in this example because the Y values in both equations are opposites of each other making it easier for you to just cancel them out.
x+2y=10
-2x-y=1
In this case you could use either substitution or eliminations. Its better for you to use whichever method makes you more comfortable.
4x+y =6
y = 2x
3x + y = -7
x-y = -5
3x -2y =0
9x + 8y = 7
3-3 Explain how to determine which region to shade to indicate the solution set of a system of linear inequalities.
3-4 Explain the meaning of the constraints, feasible region, vertices, and objective function in a Linear Programming problem.
BRITT:
Linear Programing Problem is a way to find the max and the min of a function and it has to satisfy a given set of conditions called constraints. Constraints are the inequalities in a linear programing problem usually making up a feasible region. Feasible region is the region on a graph that it shaded and any poin tin that shaded region can be an answer to the linear programing problem.
Objective function is the best combonation of values inorder to min or max a certain function.
the oeach color in this picture is the feasible region that is made up of the constraints which are the colored lines.
5-1 Explain the vertical and horizontal translations, reflection, vertical stretch and compression in parabolas.
A parabola opens upward if a > 0 and it opens downward if a < 0.
The axis of symmetry is the vertical is the vertical
5-2 What are the properties of a parabola. (see the Get Organized section of this chapter).
5-3 Explain how to factor using the x-box method. When do you find a zero of a function and how? When do you find a root of an equation and how?
5-4 Explain how to convert a quadratic equation from standard to vertex form?
Natalie:
Section 5-4: Completing the square, converting a quadratic equation into vertex form
Vertex form: f(x) = a (x - h)² + k
- set up equation to complete the square
- add (b/2)² to one side, and subtract (b/2)² to the other side
- (b/2) not squared is the number (x ± (b/2))
- simplify and factor
- vertex: (h , k) Ex:
5-5 Complete the Get Organized problem on pg 352. Explain the parts of a complex number.
Natalie:
Section 5-5: Completing “Get Organized!”, Complex Numbers Get Organized!
Complex Numbers Real Numbers:Imaginary Numbers:
3 √-9
√54 6i
-645 √-675
.583 5i√3
3.14
A complex number is a number that can be written in the form a + bi, where a and b are real numbers and i = √-1. The real part of a complex number is a. the imaginary part is bi.
Ex:
Dan: in a complex number there are 2 parts, the imaginary part and the real part. Complex numbers are written as a+bi. which (a) is the real part and (bi) is the imaginary part.
Britt: the imaginanry number it the square root of a negitive. it is imaginary because not one number you square will ever come out to be negitive and that is way it is imaginary opposed to the real numbers.
REAL NUMBERS Rational or irrational #s. an number
represented on the number line.
1,55,1/4,-66
Imaginary Numbers
The square root of a negative number, written in the form bi.
i
5-6 f(x)={-b±(square root of)b²-4ac}/2a 1. get the equation into standard form. (ax²+bx+c)
2. plug in a, b and c into the quadratic formula
3. solve.
You are expected to sign up for AT LEAST 2 sections. Besides giving some explanation about the section you must answer the BIG IDEA Question for your section. You may need to do some work and use photobooth to take a picture of your work and post it on the page.
3-2 You would like to minimize the amount of work required to solve a system of equations. Tell whether you would solve each system using substitution or elimination and why.
Michelle: In order to solves this system of equations you must first look at each equation individually.
y=2
Subtract 2 from both sides. The equation is now 2x=16.
Then divide both sides by 2 and get x=8.
x-y=-5
X=-3
Then plug in the X value to either of the original equations to get the Y
-2x-y=1
y = 2x
x-y = -5
9x + 8y = 7
3-3 Explain how to determine which region to shade to indicate the solution set of a system of linear inequalities.
3-4 Explain the meaning of the constraints, feasible region, vertices, and objective function in a Linear Programming problem.
BRITT:
Linear Programing Problem is a way to find the max and the min of a function and it has to satisfy a given set of conditions called constraints. Constraints are the inequalities in a linear programing problem usually making up a feasible region. Feasible region is the region on a graph that it shaded and any poin tin that shaded region can be an answer to the linear programing problem.
Objective function is the best combonation of values inorder to min or max a certain function.
the oeach color in this picture is the feasible region that is made up of the constraints which are the colored lines.
5-1 Explain the vertical and horizontal translations, reflection, vertical stretch and compression in parabolas.
A parabola opens upward if a > 0 and it opens downward if a < 0.
The axis of symmetry is the vertical is the vertical
5-2 What are the properties of a parabola. (see the Get Organized section of this chapter).
5-3 Explain how to factor using the x-box method. When do you find a zero of a function and how? When do you find a root of an equation and how?
5-4 Explain how to convert a quadratic equation from standard to vertex form?
Natalie:
Section 5-4: Completing the square, converting a quadratic equation into vertex form
Vertex form: f(x) = a (x - h)² + k
- set up equation to complete the square
- add (b/2)² to one side, and subtract (b/2)² to the other side
- (b/2) not squared is the number (x ± (b/2))
- simplify and factor
- vertex: (h , k)
5-5 Complete the Get Organized problem on pg 352. Explain the parts of a complex number.
Natalie:
Section 5-5: Completing “Get Organized!”, Complex Numbers
Get Organized!
Complex Numbers
Real Numbers: Imaginary Numbers:
3 √-9
√54 6i
-645 √-675
.583 5i√3
3.14
A complex number is a number that can be written in the form a + bi, where a and b are real numbers and i = √-1. The real part of a complex number is a. the imaginary part is bi.
Dan: in a complex number there are 2 parts, the imaginary part and the real part. Complex numbers are written as a+bi. which (a) is the real part and (bi) is the imaginary part.
Britt: the imaginanry number it the square root of a negitive. it is imaginary because not one number you square will ever come out to be negitive and that is way it is imaginary opposed to the real numbers.
Rational or irrational #s. an number
represented on the number line.
1,55,1/4,-66
The square root of a negative number, written in the form bi.
i
5-6
f(x)={-b±(square root of)b²-4ac}/2a
1. get the equation into standard form. (ax²+bx+c)
2. plug in a, b and c into the quadratic formula
3. solve.